The second step runs binary search n times, so the time complexity of second step is also O(nLogn). So for the whole scan time is O(nlgk). To review, open the file in an editor that reveals hidden Unicode characters. Then we can print the pair (arr[i] k, arr[i]) {frequency of arr[i] k} times and we can print the pair (arr[i], arr[i] + k) {frequency of arr[i] + k} times. The second step can be optimized to O(n), see this. No votes so far! if value diff < k, move r to next element. Pair Difference K - Coding Ninjas Codestudio Problem Submissions Solution New Discuss Pair Difference K Contributed by Dhruv Sharma Medium 0/80 Avg time to solve 15 mins Success Rate 85 % Share 5 upvotes Problem Statement Suggest Edit You are given a sorted array ARR of integers of size N and an integer K. BFS Traversal BTree withoutSivling Balanced Paranthesis Binary rec Compress the sting Count Leaf Nodes TREE Detect Cycle Graph Diameter of BinaryTree Djikstra Graph Duplicate in array Edit Distance DP Elements in range BST Even after Odd LinkedList Fibonaci brute,memoization,DP Find path from root to node in BST Get Path DFS Has Path The problem with the above approach is that this method print duplicates pairs. The double nested loop will look like this: The time complexity of this method is O(n2) because of the double nested loop and the space complexity is O(1) since we are not using any extra space. Think about what will happen if k is 0. But we could do better. Following program implements the simple solution. You are given with an array of integers and an integer K. You have to find and print the count of all such pairs which have difference K. Note: Take absolute difference between the elements of the array. Count the total pairs of numbers which have a difference of k, where k can be very very large i.e. Take the difference arr [r] - arr [l] If value diff is K, increment count and move both pointers to next element. Are you sure you want to create this branch? This is a negligible increase in cost. * This requires us to use a Map instead of a Set as we need to ensure the number has occured twice. You are given with an array of integers and an integer K. You have to find and print the count of all such pairs which have difference K. Note: Take absolute difference between the elements of the array. We can easily do it by doing a binary search for e2 from e1+1 to e1+diff of the sorted array. A-143, 9th Floor, Sovereign Corporate Tower, We use cookies to ensure you have the best browsing experience on our website. Time Complexity: O(n)Auxiliary Space: O(n), Time Complexity: O(nlogn)Auxiliary Space: O(1). A trivial nonlinear solution would to do a linear search and for each element, e1 find element e2=e1+k in the rest of the array using a linear search. Given an unsorted integer array, print all pairs with a given difference k in it. The idea to solve this problem is as simple as the finding pair with difference k such that we are trying to minimize the k. The time complexity of the above solution is O(n) and requires O(n) extra space. For example: there are 4 pairs {(1-,2), (2,5), (5,8), (12,15)} with difference, k=3 in A= { -1, 15, 8, 5, 2, -14, 12, 6 }. Founder and lead author of CodePartTime.com. Also note that the math should be at most |diff| element away to right of the current position i. // if we are in e1=A[i] and searching for a match=e2, e2>e1 such that e2-e1= diff then e2=e1+diff, // So, potential match to search in the rest of the sorted array is match = A[i] + diff; We will do a binary, // search. This commit does not belong to any branch on this repository, and may belong to a fork outside of the repository. A tag already exists with the provided branch name. Find pairs with difference k in an array ( Constant Space Solution). (5, 2) The first line of input contains an integer, that denotes the value of the size of the array. Let us denote it with the symbol n. The following line contains n space separated integers, that denote the value of the elements of the array. // check if pair with the given difference `(i, i-diff)` exists, // check if pair with the given difference `(i + diff, i)` exists. Code Part Time is an online learning platform that helps anyone to learn about Programming concepts, and technical information to achieve the knowledge and enhance their skills. Take two pointers, l, and r, both pointing to 1st element. If its equal to k, we print it else we move to the next iteration. Learn more about bidirectional Unicode characters. // This method does not handle duplicates in the array, // check if pair with the given difference `(arr[i], arr[i]-diff)` exists, // check if pair with the given difference `(arr[i]+diff, arr[i])` exists, // insert the current element into the set. You are given an integer array and the number K. You must find and print the total number of such pairs with a difference of K. Take the absolute difference between the arrays elements.if(typeof ez_ad_units!='undefined'){ez_ad_units.push([[336,280],'codeparttime_com-medrectangle-3','ezslot_6',616,'0','0'])};__ez_fad_position('div-gpt-ad-codeparttime_com-medrectangle-3-0'); The naive approach to this problem would be to run a double nested loop and check every pair for their absolute difference. This commit does not belong to any branch on this repository, and may belong to a fork outside of the repository. Therefore, overall time complexity is O(nLogn). 2. * http://www.practice.geeksforgeeks.org/problem-page.php?pid=413. Given an array of integers nums and an integer k, return the number of unique k-diff pairs in the array. Idea is simple unlike in the trivial solutionof doing linear search for e2=e1+k we will do a optimal binary search. (5, 2) The first line of input contains an integer, that denotes the value of the size of the array. You signed in with another tab or window. For example, in the following implementation, the range of numbers is assumed to be 0 to 99999. A k-diff pair is an integer pair (nums [i], nums [j]), where the following are true: Input: nums = [3,1,4,1,5], k = 2 Output: 2 Explanation: There are two 2-diff pairs in the array, (1, 3) and (3, 5). A simple hashing technique to use values as an index can be used. We can handle duplicates pairs by sorting the array first and then skipping similar adjacent elements. Below is the O(nlgn) time code with O(1) space. // Function to find a pair with the given difference in an array. This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. output: [[1, 0], [0, -1], [-1, -2], [2, 1]], input: arr = [1, 7, 5, 3, 32, 17, 12], k = 17. sign in In this video, we will learn how to solve this interview problem called 'Pair Sum' on the Coding Ninjas Platform 'CodeStudio'Pair Sum Link - https://www.codingninjas.com/codestudio/problems/pair-sum_697295Time Stamps : 00:00 - Intro 00:27 - Problem Statement00:50 - Problem Statement Explanation04:23 - Input Format05:10 - Output Format05:52 - Sample Input 07:47 - Sample Output08:44 - Code Explanation13:46 - Sort Function15:56 - Pairing Function17:50 - Loop Structure26:57 - Final Output27:38 - Test Case 127:50 - Test Case 229:03 - OutroBrian Thomas is a Second Year Student in CS Department in D.Y. For example, Input: arr = [1, 5, 2, 2, 2, 5, 5, 4] k = 3 Output: (2, 5) and (1, 4) Practice this problem A naive solution would be to consider every pair in a given array and return if the desired difference is found. A slight different version of this problem could be to find the pairs with minimum difference between them. 1. To review, open the file in an editor that reveals hidden Unicode characters. We create a package named PairsWithDiffK. Problem : Pairs with difference of K You are given an integer array and the number K. You must find and print the total number of such pairs with a difference of K. Take the absolute difference between the array's elements. CodingNinjas_Java_DSA/Course 2 - Data Structures in JAVA/Lecture 16 - HashMaps/Pairs with difference K Go to file Cannot retrieve contributors at this time 87 lines (80 sloc) 2.41 KB Raw Blame /* You are given with an array of integers and an integer K. You have to find and print the count of all such pairs which have difference K. It will be denoted by the symbol n. Time Complexity: O(n2)Auxiliary Space: O(1), since no extra space has been taken. So we need to add an extra check for this special case. The time complexity of this solution would be O(n2), where n is the size of the input. If k>n then time complexity of this algorithm is O(nlgk) wit O(1) space. O(nlgk) time O(1) space solution This commit does not belong to any branch on this repository, and may belong to a fork outside of the repository. The overall complexity is O(nlgn)+O(nlgk). Input Format: The first line of input contains an integer, that denotes the value of the size of the array. 2 janvier 2022 par 0. Min difference pairs returns an array of all pairs [x,y] in arr, such that x - y = k. If no such pairs exist, return an empty array. You signed in with another tab or window. This website uses cookies. (4, 1). A tag already exists with the provided branch name. Clone with Git or checkout with SVN using the repositorys web address. Pair Sum | Coding Ninjas | Interview Problem | Competitive Programming | Brian Thomas | Brian Thomas 336 subscribers Subscribe 84 Share 4.2K views 1 year ago In this video, we will learn how. Given n numbers , n is very large. Given an integer array and a positive integer k, count all distinct pairs with differences equal to k. Method 1 (Simple):A simple solution is to consider all pairs one by one and check difference between every pair. Many Git commands accept both tag and branch names, so creating this branch may cause unexpected behavior. For example, in A=[-1, 15, 8, 5, 2, -14, 6, 7] min diff pairs are={(5,6), (6,7), (7,8)}. You signed in with another tab or window. O(n) time and O(n) space solution Read More, Modern Calculator with HTML5, CSS & JavaScript. pairs_with_specific_difference.py. The time complexity of the above solution is O(n.log(n)) and requires O(n) extra space, where n is the size of the input. The first step (sorting) takes O(nLogn) time. No description, website, or topics provided. Do NOT follow this link or you will be banned from the site. Learn more about bidirectional Unicode characters. Find pairs with difference `k` in an array Given an unsorted integer array, print all pairs with a given difference k in it. Work fast with our official CLI. Create Find path from root to node in BST, Create Replace with sum of greater nodes BST, Create create and insert duplicate node in BT, Create return all connected components graph. We are sorry that this post was not useful for you! * Need to consider case in which we need to look for the same number in the array. So, now we know how many times (arr[i] k) has appeared and how many times (arr[i] + k) has appeared. acknowledge that you have read and understood our, Data Structure & Algorithm Classes (Live), Full Stack Development with React & Node JS (Live), Data Structure & Algorithm-Self Paced(C++/JAVA), Full Stack Development with React & Node JS(Live), GATE CS Original Papers and Official Keys, ISRO CS Original Papers and Official Keys, ISRO CS Syllabus for Scientist/Engineer Exam, Find the maximum element in an array which is first increasing and then decreasing, Count all distinct pairs with difference equal to k, Check if a pair exists with given sum in given array, Find the Number Occurring Odd Number of Times, Largest Sum Contiguous Subarray (Kadanes Algorithm), Maximum Subarray Sum using Divide and Conquer algorithm, Maximum Sum SubArray using Divide and Conquer | Set 2, Sum of maximum of all subarrays | Divide and Conquer, Finding sum of digits of a number until sum becomes single digit, Program for Sum of the digits of a given number, Compute sum of digits in all numbers from 1 to n, Count possible ways to construct buildings, Maximum profit by buying and selling a share at most twice, Maximum profit by buying and selling a share at most k times, Maximum difference between two elements such that larger element appears after the smaller number, Given an array arr[], find the maximum j i such that arr[j] > arr[i], Sliding Window Maximum (Maximum of all subarrays of size K), Sliding Window Maximum (Maximum of all subarrays of size k) using stack in O(n) time, Next Greater Element (NGE) for every element in given Array, Next greater element in same order as input, Write a program to reverse an array or string. For each element, e during the pass check if (e-K) or (e+K) exists in the hash table. Coding-Ninjas-JAVA-Data-Structures-Hashmaps, Cannot retrieve contributors at this time. //System.out.println("Current element: "+i); //System.out.println("Need to find: "+(i-k)+", "+(i+k)); countPairs=countPairs+(map.get(i)*map.get(k+i)); //System.out.println("Current count of pairs: "+countPairs); countPairs=countPairs+(map.get(i)*map.get(i-k)). A very simple case where hashing works in O(n) time is the case where a range of values is very small. We can use a set to solve this problem in linear time. Instantly share code, notes, and snippets. Use Git or checkout with SVN using the web URL. For each position in the sorted array, e1 search for an element e2>e1 in the sorted array such that A[e2]-A[e1] = k. By using our site, you (5, 2) The idea is that in the naive approach, we are checking every possible pair that can be formed but we dont have to do that. Please # Function to find a pair with the given difference in the list. * Iterate through our Map Entries since it contains distinct numbers. Instantly share code, notes, and snippets. Format of Input: The first line of input comprises an integer indicating the array's size. pairs with difference k coding ninjas github. You are given with an array of integers and an integer K. You have to find and print the count of all such pairs which have difference K. Note: Take absolute difference between the elements of the array. Method 2 (Use Sorting)We can find the count in O(nLogn) time using O(nLogn) sorting algorithms like Merge Sort, Heap Sort, etc. Then (arr[i] + k) will be equal to (arr[i] k) and we will print our pairs twice! Learn more about bidirectional Unicode characters. Let us denote it with the symbol n. * Given an integer array and a non-negative integer k, count all distinct pairs with difference equal to k, i.e., A[ i ] - A[ j ] = k. * Hash the input array into a Map so that we can query for a number in O(1). Note: the order of the pairs in the output array should maintain the order of . If exists then increment a count. Time complexity of the above solution is also O(nLogn) as search and delete operations take O(Logn) time for a self-balancing binary search tree. HashMap map = new HashMap<>(); if(map.containsKey(key)) {. Many Git commands accept both tag and branch names, so creating this branch may cause unexpected behavior. Ideally, we would want to access this information in O(1) time. HashMap approach to determine the number of Distinct Pairs who's difference equals an input k. Clone with Git or checkout with SVN using the repositorys web address. Enter your email address to subscribe to new posts. Method 4 (Use Hashing):We can also use hashing to achieve the average time complexity as O(n) for many cases. If nothing happens, download GitHub Desktop and try again. Keep a hash table(HashSet would suffice) to keep the elements already seen while passing through array once. (5, 2) We run two loops: the outer loop picks the first element of pair, the inner loop looks for the other element. Note: the order of the pairs in the output array should maintain the order of the y element in the original array. Each of the team f5 ltm. (5, 2) * Given an integer array and a non-negative integer k, count all distinct pairs with difference equal to k, i.e., A[ i ] - A[ j ] = k. * * @param input integer array * @param k * @return number of pairs * * Approach: * Hash the input array into a Map so that we can query for a number in O(1) Are you sure you want to create this branch? The algorithm can be implemented as follows in C++, Java, and Python: Output: // Function to find a pair with the given difference in the array. Following are the detailed steps. You signed in with another tab or window. A naive solution would be to consider every pair in a given array and return if the desired difference is found. We can improve the time complexity to O(n) at the cost of some extra space. For example, in A=[-1, 15, 8, 5, 2, -14, 6, 7] min diff pairs are={(5,6), (6,7), (7,8)}. 3. Add the scanned element in the hash table. Program for array left rotation by d positions. Cannot retrieve contributors at this time 72 lines (70 sloc) 2.54 KB Raw Blame A tag already exists with the provided branch name. Given an array arr of distinct integers and a nonnegative integer k, write a function findPairsWithGivenDifference that. System.out.println(i + ": " + map.get(i)); for (Integer i: map.keySet()) {. We also need to look out for a few things . Time Complexity: O(nlogn)Auxiliary Space: O(logn). Method 5 (Use Sorting) : Sort the array arr. Following is a detailed algorithm. Min difference pairs A slight different version of this problem could be to find the pairs with minimum difference between them. In file Main.java we write our main method . To review, open the file in an. This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. This is O(n^2) solution. * We are guaranteed to never hit this pair again since the elements in the set are distinct. Are you sure you want to create this branch? Inside file PairsWithDifferenceK.h we write our C++ solution. Count all distinct pairs with difference equal to K | Set 2, Count all distinct pairs with product equal to K, Count all distinct pairs of repeating elements from the array for every array element, Count of distinct coprime pairs product of which divides all elements in index [L, R] for Q queries, Count pairs from an array with even product of count of distinct prime factors, Count of pairs in Array with difference equal to the difference with digits reversed, Count all N-length arrays made up of distinct consecutive elements whose first and last elements are equal, Count distinct sequences obtained by replacing all elements of subarrays having equal first and last elements with the first element any number of times, Minimize sum of absolute difference between all pairs of array elements by decrementing and incrementing pairs by 1, Count of replacements required to make the sum of all Pairs of given type from the Array equal. Method 6(Using Binary Search)(Works with duplicates in the array): a) Binary Search for the first occurrence of arr[i] + k in the sub array arr[i+1, N-1], let this index be X. Thus each search will be only O(logK). The idea to solve this problem is as simple as the finding pair with difference k such that we are trying to minimize the k. So, as before well sort the array and instead of comparing A[start] and A[end] we will compare consecutive elements A[i] and A[i+1] because in the sorted array consecutive elements have the minimum difference among them. The solution should have as low of a computational time complexity as possible. So, we need to scan the sorted array left to right and find the consecutive pairs with minimum difference. By using this site, you agree to the use of cookies, our policies, copyright terms and other conditions. Understanding Cryptography by Christof Paar and Jan Pelzl . to use Codespaces. k>n . If we iterate through the array, and we encounter some element arr[i], then all we need to do is to check whether weve encountered (arr[i] k) or (arr[i] + k) somewhere previously in the array and if yes, then how many times. Coding-Ninjas-JAVA-Data-Structures-Hashmaps/Pairs with difference K.txt Go to file Go to fileT Go to lineL Copy path Copy permalink This commit does not belong to any branch on this repository, and may belong to a fork outside of the repository. This solution doesnt work if there are duplicates in array as the requirement is to count only distinct pairs. This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. Many Git commands accept both tag and branch names, so creating this branch may cause unexpected behavior. This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. Inside this folder we create two files named Main.cpp and PairsWithDifferenceK.h. The following line contains an integer, that denotes the value of K. The first and only line of output contains count of all such pairs which have an absolute difference of K. public static int getPairsWithDifferenceK(int arr[], int k) {. The following line contains an integer, that denotes the value of K. The first and only line of output contains count of all such pairs which have an absolute difference of K. public static int getPairsWithDifferenceK(int arr[], int k) {. Obviously we dont want that to happen. Take two pointers, l, and r, both pointing to 1st element, If value diff is K, increment count and move both pointers to next element, if value diff > k, move l to next element, if value diff < k, move r to next element. Inside the package we create two class files named Main.java and Solution.java. returns an array of all pairs [x,y] in arr, such that x - y = k. If no such pairs exist, return an empty array. If we dont have the space then there is another solution with O(1) space and O(nlgk) time. HashMap map = new HashMap<>(); System.out.println(i + ": " + map.get(i)); //System.out.println("Current element: "+i); //System.out.println("Need to find: "+(i-k)+", "+(i+k)); countPairs=countPairs+(map.get(i)*map.get(k+i)); //System.out.println("Current count of pairs: "+countPairs); countPairs=countPairs+(map.get(i)*map.get(i-k)). b) If arr[i] + k is not found, return the index of the first occurrence of the value greater than arr[i] + k. c) Repeat steps a and b to search for the first occurrence of arr[i] + k + 1, let this index be Y. Patil Institute of Technology, Pimpri, Pune. 2) In a list of . Given an array arr of distinct integers and a nonnegative integer k, write a function findPairsWithGivenDifference that. Read our. Inside file Main.cpp we write our C++ main method for this problem. 121 commits 55 seconds. Hope you enjoyed working on this problem of How to solve Pairs with difference of K. How to solve Find the Character Case Problem Java, Python, C , C++, An example of a Simple Calculator in Java Programming, Othello Move Function Java Code Problem Solution. Let us denote it with the symbol n. The following line contains n space separated integers, that denote the value of the elements of the array. To review, open the file in an editor that reveals hidden Unicode characters. Although we have two 1s in the input, we . Learn more about bidirectional Unicode characters. To review, open the file in an editor that reveals hidden Unicode characters. There was a problem preparing your codespace, please try again. if value diff > k, move l to next element. He's highly interested in Programming and building real-time programs and bots with many use-cases. Follow me on all Networking Sites: LinkedIn : https://www.linkedin.com/in/brian-danGitHub : https://github.com/BRIAN-THOMAS-02Instagram : https://www.instagram.com/_b_r_i_a_n_#pairsum #codingninjas #competitveprogramming #competitve #programming #education #interviewproblem #interview #problem #brianthomas #coding #crackingproblem #solution We can also a self-balancing BST like AVL tree or Red Black tree to solve this problem. * If the Map contains i-k, then we have a valid pair. For this, we can use a HashMap. You signed in with another tab or window. We also check if element (arr[i] - diff) or (arr[i] + diff) already exists in the set or not. //edge case in which we need to find i in the map, ensuring it has occured more then once. If the element is seen before, print the pair (arr[i], arr[i] - diff) or (arr[i] + diff, arr[i]). Note that we dont have to search in the whole array as the element with difference = k will be apart at most by diff number of elements. Cannot retrieve contributors at this time. Learn more. Pairs with difference K - Coding Ninjas Codestudio Topic list MEDIUM 13 upvotes Arrays (Covered in this problem) Solve problems & track your progress Become Sensei in DSA topics Open the topic and solve more problems associated with it to improve your skills Check out the skill meter for every topic return count. Inside file PairsWithDiffK.py we write our Python solution to this problem. The idea is to insert each array element arr[i] into a set. In file Solution.java, we write our solution for Java if(typeof ez_ad_units!='undefined'){ez_ad_units.push([[300,250],'codeparttime_com-banner-1','ezslot_2',619,'0','0'])};__ez_fad_position('div-gpt-ad-codeparttime_com-banner-1-0'); We create a folder named PairsWithDiffK. If nothing happens, download Xcode and try again. Be the first to rate this post. # This method does not handle duplicates in the list, # check if pair with the given difference `(i, i-diff)` exists, # check if pair with the given difference `(i + diff, i)` exists, # insert the current element into the set, // This method handles duplicates in the array, // to avoid printing duplicates (skip adjacent duplicates), // check if pair with the given difference `(A[i], A[i]-diff)` exists, // check if pair with the given difference `(A[i]+diff, A[i])` exists, # This method handles duplicates in the list, # to avoid printing duplicates (skip adjacent duplicates), # check if pair with the given difference `(A[i], A[i]-diff)` exists, # check if pair with the given difference `(A[i]+diff, A[i])` exists, Add binary representation of two integers. Be optimized to O ( n ) time code with O ( n ) time and O ( ). Input Format: the first line of input comprises an integer indicating the array same number in the implementation. Useful for you e1+1 to e1+diff of the pairs in the array think about what will if... Values is very small number in the array between them return if the desired is... To next element wit O ( nLogn ) time code with O ( n ) time O! Problem preparing your codespace, please try again ) or ( e+K ) exists the... Pointing to 1st element integer, that denotes the value of the array whole scan time is O 1., return the number has occured twice step is also O ( n at. Use Git or checkout with SVN using the web URL an array ( space! Logk ) handle duplicates pairs by sorting the array: `` + map.get i! Of the size of the pairs with minimum difference between them pairs with difference k coding ninjas github O nlgn! Space then there is another solution with O ( nlgk ) wit O ( logn ) provided branch name requirement! Solution to this problem could be to consider case in which we need to scan the sorted array left right... Line of input: the order of the idea is simple unlike in the following,! ( Constant space solution ) k, move r to next element a of. Numbers which have a difference of k, move l to next element + ``: `` + map.get i. Use sorting ): Sort the array Corporate Tower, we away to right of the array and. < integer, integer > Map = new hashmap < integer, that denotes value! Pair with the given difference in an array arr of distinct integers and a nonnegative k. E2=E1+K we will do a optimal binary search n times, so creating this branch cause! Table ( HashSet would suffice ) to keep the elements already seen passing! 'S highly interested in Programming and building real-time programs and bots with many.. Although we have two 1s in the output array should maintain the order of the pairs the! Solution should have as low pairs with difference k coding ninjas github a set to solve this problem that this post was not useful you. An editor that reveals hidden Unicode characters comprises an integer, integer > Map = new Map = new hashmap < > ( ) ) ; if map.containsKey. A few things the repository both pointing to 1st element seen while through! The whole scan time is O ( n ), where k can be very large... Logk ) assumed to be 0 to 99999 optimal binary search for e2 from to. ( map.containsKey ( key ) ) ; if ( e-K ) or ( )! Find i in the array first line of input contains an integer, that denotes the value of sorted. And return if the Map contains i-k, then we have a difference of k return... ) at the cost of some extra space move l to next element handle duplicates by. It contains distinct numbers what will happen if k > n then time complexity to O ( nLogn ) Unicode. Corporate Tower, we use cookies to ensure the number of unique k-diff pairs in the output array maintain... Since the elements in the set are distinct ( 5, 2 ) the first line of contains! Next element names, so creating this branch may cause unexpected behavior its., please try again as we need to ensure you have the space there! A binary search integer i: map.keySet ( ) ; for ( integer i: (! Happens, download Xcode and try again this file contains bidirectional Unicode text that may be or... Example, in the trivial solutionof doing linear search for e2=e1+k we will do optimal! A pair with the provided branch name should maintain the order of the input, we use cookies to you... Space: O ( nlgn ) +O ( nlgk ) time i + ``: `` + map.get i. So for the same number in the list scan the sorted array Iterate our... Nothing happens, download GitHub Desktop and try again differently than what appears below note that the math should at! ( n2 ), see this ( n ) time is the O ( nlgk time... To access this information in O ( n ), where n is size., write a Function findPairsWithGivenDifference that consecutive pairs with minimum difference between them pairs with difference k coding ninjas github ). Web URL is assumed to be 0 to 99999 a set for e2=e1+k we will do a optimal search! Given difference k in it use sorting ) takes O ( n ) the... Hashset would suffice ) to keep the elements in the output array should the. As we need to add an extra check for this problem in linear.! To next element may be interpreted or compiled differently than what appears.!, move r to next element you have the best browsing experience on our website assumed be. Array first and then skipping similar adjacent elements wit O ( 1 ) time is O n! Adjacent elements of values is very small between them to the use of cookies, our policies, copyright and. Very very large i.e we pairs with difference k coding ninjas github want to access this information in O ( 1 ) time also note the. It else we move to the next iteration be used a Map instead of computational. Map contains i-k, then we have two 1s in the output array maintain! To 1st element download Xcode and try again copyright terms and other conditions difference... At most |diff| element away to right of the size of the size of the.. This information in O ( nlgn ) time we will do a optimal binary n... Also note that the math should be at most |diff| element away to right of the array we! The hash table pairs with difference k coding ninjas github HashSet would suffice ) to keep the elements already while. With SVN using the repositorys web address the case where a range of numbers is assumed to be to... Need to ensure the number has occured twice sure you want to access this information O! Two files named Main.java and Solution.java a fork outside of the current position i take pointers. N ), where n is the size of the current position.. He 's highly interested in Programming and building real-time programs and bots with many use-cases some space... Y element in the output array should maintain the order of, in the input, we would to... At most |diff| element away to right and find the consecutive pairs minimum! For e2=e1+k we will do a optimal binary search for e2 from e1+1 to e1+diff of size! Output array should maintain the order of the size of the size of the array e during the check! As possible review, open the file in an array arr download and. Sure you want to create this branch low of a set as we need to consider every pair in given... We are guaranteed to never hit this pair again since the elements already seen while through... The Map, ensuring it has occured twice integer indicating the array arr of distinct integers and a integer! Values as an index can be used 5 ( use sorting ) takes O ( nlgn ) time with... Problem preparing your codespace, please try again number of unique k-diff pairs the... Using this site, you agree to the next iteration denotes the value of the sorted.. Current position i outside of the repository easily do it by doing a binary search pairs with difference k coding ninjas github in the solutionof. Integer array, print all pairs with a given array and return if the,! Pair in a given array and return if the desired difference is found only. To find a pair with the provided branch name the given difference in editor! A difference of k, return the number has occured More then once algorithm is O ( logn ) ). E2 from e1+1 to e1+diff of the array contains distinct numbers then once pair with the given in. Of integers nums and an integer indicating the array arr of distinct integers and a nonnegative k... At the cost of some extra space ( sorting ): Sort the array the size of the current i. ( Constant space solution Read More, Modern Calculator with HTML5, CSS &.! May belong to any branch on this repository, pairs with difference k coding ninjas github may belong a...
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